UTME/SSCE Chemistry Practice Tests – Symbols, Formulae and Equations

Chemistry Practice Tests – Symbols, Formulae and Equations


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The law of definite proportions states that ______

(a) pure samples of the same compound contain the same elements combined in the same proportion by mass.
(b) pure samples of substances are in the same proportions by mass
(c) chemical compounds are pure because they contain the same elements.
(d) matter can neither he created nor destroyed.

Which of the following is the relative molecular mass of a compound which has empirical formula CH2O? (H = 1, C = 12, O=16)

(a) 42   (b) 45 (c) 145  (d) 180

An organic compound contains 72% carbon, 12% hydrogen and 16% oxygen by mass. What is the empirical formula of the compound? [H 1.0, C = 12.0, O = 16.0]

(a) C3H8O      (b) C6H12O     (c) C6H12O2       (d) C12H12O11

What is the total volume of the residual gas formed when 20 cm3 of hydrogen is sparked in 15 cm3 of oxygen at a temperature of 150°C according to the following equation?

2H2(g) + O2(g) —> 2H2O(g)

(a) 10 cm3 (b) 15 cm3 (c) 25 cm3 (d) 30 cm3

3Cu + pHNO3  3Cu(NO3)2 + xNO + 4H2O

In the equation above, the value p and x respectively are ______

(a) 1 and 3 (b) 2 and 3 (c) 6 and 2 (d) 8 and 2

Which of the following pairs of components have the same molecular mass? [H = 1.0, C = 12.0, O = 16.0]

(a) Ethene and ethyne
(b) Ethane and ethene
(c) Carbon(II) oxide and ethene
(d) Carbon(IV) oxide and ethyne

2NaHCO2(s)  Na2CO3(s) + CO2(g) + H2O(l)

From the equation above, calculate the mass of the residue formed if 1 .68g of NaHCO3 ¡s decomposed [Na = 23, C = 12, O = 16, H = 1]

(a) 1.06g    (b) 2.12g   (c) 5.30 g   (d) 10.60 g

An organic compound contains 88.89% carbon and 11.11% hydrogen. Determine the empirical formula of the compound [H = 1.0, C = 12.0]

(a) CH     (b) CH2     (c) C2H3    (d) C2H5

What is the empirical formula of a hydrocarbon containing 0.08 moles of carbon and 0.32 moles of hydrogen?

(a) CH2   (b) CH3 (c) CH4 (d) C2H4

The empirical formula of a compound containing 0.067 mol Cu and 0.066 mol O is _____ [Cu = 63.5, O = 16.0]

(a) Cu2O   (b) CuO    (c) CuO2  (d) Cu2O2

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